9y''+6y'+y=0 y(0)=-5;y'(0)=4. Посмотри ответы прямо сейчас!
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The answer is =6ln(∣y∣)+27/5ln(∣y+2∣)+3/5ln(∣y-3∣)+C Perform the decomposition into partial fractions (3(4y^2-7y-12))/(y(y+2)(y-3))=A/(y)+B/(y+2)+C/(y-3) =(A(y+2)(y-3)+B(y)(y-3)+C(y)(y+2))/(y(y+2)(y-3)...
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